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The primary and secondary coils of a transformer have 50 and 1500 turns respectively. If the magnetic flux phi, linked with the primary coil is given by phi = phi_(0)+4t, where phi is in webers, t is time in seconds and phi_(0) is a constant, the output voltage across the secondary coil is |
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Answer» 120 VOLTS Number of turns across secondary `N_(s) = 1500` Magnetic flux linked with primary, `PHI=phi_(0)+4t``therefore` Voltage across the primary, `|V_(P)|=(d phi)/(dt)=(d)/(dt)(phi_(0)+4t)=4 volt`.Also, `(V_(s))/(V_(p))=(N_(s))/(N_(p))` `therefore V_(s)=((1500)/(50))xx 4=120 V`. |
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