The probability mass function of a random variable x is zero expect at

1.	The probability mass function of a random variable x is zero expect at the points x=0, 1, 2. At these points it has the value p(O) = 3c,P (1) = 4c - 10c2,P (2) =5c - 1. Determine C(a)C=2(b) C = 1/3(c) C=1(d) C=1/9
Answer» ohhhh then ANSWER is d OK NA

The probability mass function of a random variable x is zero expect at the points x=0, 1, 2. At these points it has the value p(O) = 3c,P (1) = 4c - 10c2,P (2) =5c - 1. Determine C(a)C=2(b) C = 1/3(c) C=1(d) C=1/9

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ohhhh then ANSWER is d OK NA

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The probability mass function of a random variable x is zero expect at the points x=0, 1, 2. At these points it has the value p(O) = 3c,P (1) = 4c - 10c2,P (2) =5c - 1. Determine C(a)C=2(b) C = 1/3(c) C=1(d) C=1/9​

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The probability mass function of a random variable x is zero expect at the points x=0, 1, 2. At these points it has the value p(O) = 3c,P (1) = 4c - 10c2,P (2) =5c - 1. Determine C(a)C=2(b) C = 1/3(c) C=1(d) C=1/9