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The probability of an event A occurring is 0.5 and B occurring is 0.3. If A and B are mutually exclusive events, then find the probability of neither A nor B occurring. |
Answer» Given A and B are mutually exclusive and P(A) = 0.5, P(B) = 0.3 ∴ P(A ∪ B) = P(A) + P(B) = 0.5 + 0.3 = 0.8 So, P(A’ ∩ B’) = P{(A ∪ B)’} = 1 – P(A ∪ B) = 1 – 0.8 = 0.2 |
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