The probability of getting a total of 10 in a single throw of two dice

1.	The probability of getting a total of 10 in a single throw of two dice isA. \(\frac{1}{9}\)B. \(\frac{1}{12}\) C. \(\frac{1}{6}\) D. \(\frac{5}{36}\)
Answer» As 2 dice are thrown so there are 6×6 = 36 possibilities. Let E denote the event of getting a total score of 5. E = {(4,6),(5,5),(6,4)} ∴ n(E)= 3 Hence, P(E) = \(\frac{3}{36} = \frac{1}{12}\) As our answer matches only with option (b) ∴ Option (b) is the only correct choice.

The probability of getting a total of 10 in a single throw of two dice isA. \(\frac{1}{9}\)B. \(\frac{1}{12}\) C. \(\frac{1}{6}\) D. \(\frac{5}{36}\)

Answer»

As 2 dice are thrown so there are 6×6 = 36 possibilities.

Let E denote the event of getting a total score of 5.

E = {(4,6),(5,5),(6,4)}

∴ n(E)= 3

Hence,

P(E) = \(\frac{3}{36} = \frac{1}{12}\)

As our answer matches only with option (b)

∴ Option (b) is the only correct choice.

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The probability of getting a total of 10 in a single throw of two dice isA. \(\frac{1}{9}\)B. \(\frac{1}{12}\) C. \(\frac{1}{6}\) D. \(\frac{5}{36}\)

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