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The probability of getting an even number, when a die is thrown once isA. \(\frac{1}2\)B. \(\frac{1}3\)C. \(\frac{1}6\)D.\(\frac{5}6\)

Answer»

Total numbers of elementary events are: 6 

Let E be the event of getting an even number 

Favorable events are : 2, 4, 6 

Numbers of favorable events are: 3 

P (even number on dice) = P (E) = \(\frac{3}6\) = \(\frac{1}2\)



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