1.

The probability of India winning a test match against Westindies is \(\frac{1}{2}\). Assuming independence from match to match, the probability that in a match series, India’s second win occurs at the third test is (a) \(\frac{1}{2}\) (b) \(\frac{2}{3}\) (c) \(\frac{1}{4}\) (d) \(\frac{2}{5}\)

Answer»

(c) \(\frac{1}{4}\) 

Let A = Event that India wins the match. Then, 

\(\bar{A}\) = Event that India loses the match.

P(A) = \(\frac{1}{2}\) and P(\(\bar{A}\)) = 1 - \(\frac{1}{2}\) = \(\frac{1}{2}\)  ( P(A) + P(\(\bar{A}\)) = 1)

P(Third match is India’s second winning match) 

= P(India wins the 1st match, loses 2nd match, wins 3rd match) + P(India loses 1st match, wins 2nd match, wins 3rd match)

(or)

⇒ Required probability = P(A \(\bar{A}\) A) +  P( \(\bar{A}\) A A)

= P(A) x P(\(\bar{A}\)) x P(A) + P(\(\bar{A}\)) x P(A) x P(A)

\(\frac{1}{2}\) x \(\frac{1}{2}\) x \(\frac{1}{2}\) + \(\frac{1}{2}\) x \(\frac{1}{2}\) x \(\frac{1}{2}\) = \(\frac{1}{8}\) + \(\frac{1}{8}\) = \(\frac{2}{8}\) = \(\frac{1}{4}\).



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