InterviewSolution
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The probability of selecting a red ball random from a jar that contains only red, blue and orange balls is \(\frac{1}{4}\). The probability of selecting a blue ball at random from the same jar is \(\frac{1}{3}\). If the jar contains 10 orange balls, find the total number of balls in the jar. |
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Answer» It is given that. P(getting a red ball) = \(\frac{1}{4}\) and P(getting a blue ball) = \(\frac{1}{3}\) Let P(getting an orange ball) be x. since, there are only 3 types of balls in the jar, the sum of probability of all the balls must be 1. Therefore, \(\frac{1}{4}\) + \(\frac{1}{3}\) + x = 1 ⇒ x = 1 - \(\frac{1}{4}\) - \(\frac{1}{3}\) ⇒ x = \(\frac{12-3-4}{12}\) ⇒ x = \(\frac{5}{12}\) P(getting an orange ball) = \(\frac{5}{12}\). Let the total number of balls in the jar be n. Therefore, P(getting an orange ball) = \(\frac{10}{n}\) ⇒ \(\frac{10}{n}\) = \(\frac{5}{12}\) ⇒ n = 24 Thus, the total number of balls in the jar is 24. |
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