1.

The probability of selecting a red ball random from a jar that contains only red, blue and orange balls is \(\frac{1}{4}\). The probability of selecting a blue ball at random from the same jar is \(\frac{1}{3}\). If the jar contains 10 orange balls, find the total number of balls in the jar.

Answer»

It is given that.

P(getting a red ball) = \(\frac{1}{4}\) and P(getting a blue ball) = \(\frac{1}{3}\)

Let P(getting an orange ball) be x.

since, there are only 3 types of balls in the jar, the sum of probability of all the balls must be 1.

Therefore, \(\frac{1}{4}\) + \(\frac{1}{3}\) + x = 1

⇒ x = 1 - \(\frac{1}{4}\) - \(\frac{1}{3}\)

⇒ x = \(\frac{12-3-4}{12}\)

⇒ x = \(\frac{5}{12}\)

P(getting an orange ball) = \(\frac{5}{12}\).

 Let the total number of balls in the jar be n.

Therefore,  P(getting an orange ball) = \(\frac{10}{n}\)

⇒ \(\frac{10}{n}\) = \(\frac{5}{12}\)

⇒ n = 24

Thus, the total number of balls in the jar is 24.



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