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The probability of throwing a number greater than 2 with a fair dice isA  \(\frac{3}5\)B  \(\frac{2}5\)C  \(\frac{2}3\)D  \(\frac{1}3\)

Answer»

Total numbers of elementary events are: 6 

Let E be the event of getting a number greater than 2 

Favorable outcomes are: 3, 4, 5, 6 

Numbers of favorable outcomes are: 4 

P (number>2) = P (E) = \(\frac{4}6\) = \(\frac{2}3\)



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