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The probability of throwing a number greater than 2 with a fair dice isA \(\frac{3}5\)B \(\frac{2}5\)C \(\frac{2}3\)D \(\frac{1}3\) |
Answer» Total numbers of elementary events are: 6 Let E be the event of getting a number greater than 2 Favorable outcomes are: 3, 4, 5, 6 Numbers of favorable outcomes are: 4 P (number>2) = P (E) = \(\frac{4}6\) = \(\frac{2}3\) |
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