The probability that a number selected at random from the numbers 1, 2

1.	The probability that a number selected at random from the numbers 1, 2, 3,...,15 is a multiple of 4, isA. \(\frac{4}{15}\)B. \(\frac{2}{15}\)C. \(\frac{1}{5}\)D.\(\frac{1}{3}\)
Answer» Total numbers of elementary events are: 15 Let E be the event of getting a multiple of 4 Favorable outcomes are: 4, 8, 12 Numbers of favorable outcomes are = 3 P (multiple of 4) = P (E) = \(\frac{3}{15}\) = \(\frac{1}{5}\)

The probability that a number selected at random from the numbers 1, 2, 3,...,15 is a multiple of 4, isA. \(\frac{4}{15}\)B. \(\frac{2}{15}\)C. \(\frac{1}{5}\)D.\(\frac{1}{3}\)

Answer»

Total numbers of elementary events are: 15

Let E be the event of getting a multiple of 4

Favorable outcomes are: 4, 8, 12

Numbers of favorable outcomes are = 3

P (multiple of 4) = P (E) = \(\frac{3}{15}\) = \(\frac{1}{5}\)

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The probability that a number selected at random from the numbers 1, 2, 3,...,15 is a multiple of 4, isA. \(\frac{4}{15}\)B. \(\frac{2}{15}\)C. \(\frac{1}{5}\)D.\(\frac{1}{3}\)

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