The probability that in a family of 5 members,exactly two members have birthday on sunday is:-A. `(12 xx 5^(3))//7^(5)`B. `(10 xx 6^(2))//7^(5)`C. `2//5`D. `(10 xx 6^(3))//7^(5)`

The probability that in a family of 5 members,exactly two members have

1.	The probability that in a family of 5 members,exactly two members have birthday on sunday is:-A. `(12 xx 5^(3))//7^(5)`B. `(10 xx 6^(2))//7^(5)`C. `2//5`D. `(10 xx 6^(3))//7^(5)`
Answer» Correct Answer - D A person can have his/her birthday on any one of the seven days of the week. So 5 persons can have their birthdays in `7^(5)` ways. Out of 5, three persons can have their birthdays on days other than Sundays in `6^(3)` ways and other 2 on Sundays. Hence, the required probability is `=(.^(5)C_(2) xx 6^(3))/(7^(5)) = (10 xx 6^(3))/(7^(5))` (Note that 2 persons can be selected out of 5 in `.^(5)C_(2)` ways).

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The probability that in a family of 5 members,exactly two members have birthday on sunday is:-A. `(12 xx 5^(3))//7^(5)`B. `(10 xx 6^(2))//7^(5)`C. `2//5`D. `(10 xx 6^(3))//7^(5)`

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