1.

The product formed in highest yeild in the following reaction is, CH_(3)CH_(2)CH_(2)CHBrCH_(3)+KOH overset(alc) to

Answer»

`CH_(3)CH_(2)CHOHCH_(2)CH_(3)`
`CH_(3)CH_(2)CH_(2)CH=CH_(2)`
`CH_(3)CH_(2)CH_(2)CH_(2)OH`
`CH_(3)CH_(2)CH=CHCH_(3)`

Solution :Dehydrohalogenation OCCURS according to SAYTZEFF's RULE.


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