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The product of 6ab and 12a square b is

Answer»

Answer:

8a3−b3−12a2b+6ab2

=(2 a)^{3}+(-b)^{3}+3 .(2 a)^{2} \cdot(-b)+3.2 a \cdot(-b)^{2}=(2a)3+(−b)3+3.(2a)2⋅(−b)+3.2a⋅(−b)2

=(2 a-b)^{3}=(2a−b)3

               \left[\text { Since },(a-b)^{3}=a^{3}-b^{3}-3 a^{2} b+3 a b^{2}\right][ Since ,(a−b)3=a3−b3−3a2b+3ab2]

Factorization is defined as PROCESS of finding the LEAST factor or least divisible factor by which the given NUMBER is divisible. They can be EITHER a prime factor or any whole number which divides the number exactly. Factorization is of two types prime factorization and normal L-division 

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