1.

The product of two numbers is 3/2 . if one of the numbers is -9/20 , find the other ​

Answer»

{\blue{\underline{\underline{\purple{\textsf{\textbf{Answer : }}}}}}}

\longrightarrow \sf \frac{10}{3} \\

{\blue{\underline{\underline{\purple{\textsf{\textbf{Explanation : }}}}}}}

Given that, the product of two NUMBERS is \rm \dfrac{3}{2} \\. And one of them is \rm - \dfrac{9}{20}

If we ASSUME the other number as x

Equation can be formed :

\\  \rm \longrightarrow  \frac{ -  9}{20}  \times x =  \frac{3}{2}  \\

According to the QUESTION :

\sf ⇒ \:  \frac{ - 9x}{20}  =  \frac{3}{2}  \\

\sf ⇒ \: x =  \frac{3 \times  {20}}{  2 \times (- 9) }  \\

\sf ⇒ \: x =   \frac{ - 60}{18}  \\

\green{\sf ⇒ x = - \frac{10}{3}  \: ans}

{\blue{\underline{\underline{\purple{\textsf{\textbf{Hence, The other number is :}}}}}}}

\huge \longrightarrow \sf - \frac{10}{3} \\

NOTE behind :

  • Here, a product is given of two numbers where a number is mentioned definitely and on the other hand we have assumed the number as x . So, forming an equation get the VALUE of x will be the other number.


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