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The product p of the nuclear reaction ._(92)^(235)U + ._(0)^(1) n rarr p + ._(36)^(92)Kr + 3 ._(0)^(1)n is |
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Answer» `._(56)^(141)Sr` `._(92)U^(235) + ._(0)^(1) n rarr ._(56)Ba^(141) + ._(36)Kr^(92) + 3_(0)^(1) n` |
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