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The product p of the nuclear reaction ""_(92)^(235)U + ""_(0)^(1)n to p + ""_(36)^(92)Kr + 3 ""_(0)^(1)n is |
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Answer» `""_(56)^(141)Sr` `""_(92)U^(235) + ""_(0)^(1)n to ""_(56)Ba^(41) + ""_(36)Kr^(92) + 3 ""_(0)^(1)n` |
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