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The prong of an electrically operated tuning fork is connected to a long string of `mu=1 kg//m` and tension 25 N, the maximum velocity of the prong is `1 cm//s`, then the average power needed to drive the prong is A. `5xx10^(-4) W`B. `2.5xx10^(-4)W`C. `1xx10^(-4)W`D. `10^(-3)W` |
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Answer» Correct Answer - b Wave velocity: `v=sqrt((F)/(mu))=sqrt((25)/(1))=5 m//s` Average power: `p_(av)=(1)/(2)muv(omegaA)^(2)` `=(1)/(2)muv(v_(p-max))^(2)=(1)/(2)xx1xx5(1xx10^(-2))^(2)` `=2.5xx10^(-4) W` |
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