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The propagation constant of a wave with attenuation and phase constant given by 2 and 3 respectively is(a) 2 – 3j(b) 3 – 2j(c) 2 + 3j(d) 3 + 2jI had been asked this question in examination.This key question is from Transmission Line Secondary Parameters topic in division Transmission Lines of Electromagnetic Theory

Answer»

Right answer is (C) 2 + 3j

The EXPLANATION: The propagation CONSTANT is GIVEN by γ = α + jβ. Given that α = 2 and β = 3. Thus we get the propagation constant as γ = 2 + 3j.



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