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The proposition (p = ~p) ^ (~p = p)is a |
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Answer» <P> p ∼p p⇒∼p ∼p⇒p (p⇒∼p)∧(∼p⇒p) T F F T F F T T F F CLEARLY, (p⇒∼p)∧(∼p⇒p) is a CONTRADICTION. |
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