1.

The proposition (p = ~p) ^ (~p = p)is a​

Answer»

<P> p ∼p p⇒∼p ∼p⇒p (p⇒∼p)∧(∼p⇒p)

T F F T F

F T T F F

CLEARLY, (p⇒∼p)∧(∼p⇒p) is a CONTRADICTION.



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