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The putial pressure of ethane over a saturated solution containing 6.56 xx 10^(-2) g of ethane is 1 bar.if the solution contains 5.0 xx 10^(-2) g of ethane, then what will be the partial pressure of the gas ? |
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Answer» Solution :Let the Henry.s law constant be `K_(H)` and no. of MOLES of solvent be M. Partial pressure of ethane = `K_(H)` x mole fraction of ethane ` I = K_(H) XX (6.56 xx 10^(-2))/((30)/(M)) ` `K_(H) = (M xx 30)/(6.56 xx 10^(-2))` Now the partial pressure of ethane containing 5.0 `xx 10^(-2)` will be ` = (M xx 30)/(6.56 xx 10^(-2)) xx (5.0 xx 10^(-2))/(30 xx M)` = 0.762 BAR. |
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