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The quantity of heat (in J) required to raise temperature of 1.0 kg of ethanol from 293.45 K to the boiling point and then change the liquid to vapor at that temperature is closest to [Given , Boiling point of ethanol 351.45K] Specific heat capacity of liquid ethanol `2.44Jg^(-1)K^(-1)` latent heat of vaporization of ethanol `855Jg^(-1)K^(-1)`A. `1.42xx10^(2)`B. `9.97xx10^(2)`C. `1.42xx1^(5)`D. `9.97xx10^(5)` |
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Answer» Correct Answer - D `q=mc Deltat+"heat of vapourisation"` `=100xx2.44(351.45-293.45)+855xx1000J` `=9.97xx10^(5)J` |
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