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The question in which I am facing problem is : Three prizes are to be distributed in a quiz contest. The value of second prize is 5/6 of the value of first prize and the value of third prize is 4/5 of second prize. If the total value of three prizes is Rs.1500. Find the value of each prize. (in order of 1st, 2nd & 3rd The solution which was given to me was: Let the value of first prize = x Value of second prize = 56x Value of third prize = 45 (Value of the second prize) = 45 (56x) = 23x Total value of three prizes = Rs.1500 ⇒x+56x+23x=1500 ⇒ 6x+5x+4x6=1500 ⇒ 15x6=1500 ⇒x=600 Value of first prize = Rs. 600 Value of second prize = 56 × Rs. 600 = Rs. 500 Value of third prize = 23 × Rs. 600 = Rs. 400 Now, my doubt is that why was 2/3x taken in the equation ? It was not mentioned in the question |
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Answer» The question in which I am facing problem is : Three prizes are to be distributed in a quiz contest. The value of second prize is 5/6 of the value of first prize and the value of third prize is 4/5 of second prize. If the total value of three prizes is Rs.1500. Find the value of each prize. (in order of 1st, 2nd & 3rd The solution which was given to me was: Let the value of first prize = x Value of second prize = 56x Value of third prize = 45 (Value of the second prize) = 45 (56x) = 23x Total value of three prizes = Rs.1500 ⇒x+56x+23x=1500 Now, my doubt is that why was 2/3x taken in the equation ? It was not mentioned in the question |
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