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Answer:

As triangle ABCD =triangle PQRS

side of the square PQRS= 20cm

area of triangle PQRS = S×S

= 20×20

=400 sq cm

let the SIDES of triangle ABCD be 2x and 3x

= area of the triangle=S×S

400= 2x × 3x

400= 6x^2

400÷6 = X^2

66.66 =x^2

√66.66= x

8.16= x

2x= 2 × x = 2×8.16=16.32

3x= 3×x= 3 × 8.16= 24.48


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