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The r.m.s. speed of oxygen is v at a particular temperature. If the temperature is doubled and oxygen molecule dissociate into oxygen atoms, the r.m.s. speed becomes |
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Answer» v For OXYGEN molecules at temperature T, `v_(rms)=v=sqrt((3RT)/(M))""...(i)` Now, temperature is doubled and oxygen molecules dissociate into oxygen atom (molar mass BECOMES `M//2`) then rms speed will be `v._(rms)=sqrt((3R(2T))/((M//2)))=2sqrt((3RT)/(M))=2v` [USING eqn(i)] |
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