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The r.m.s. speed of the molecules of a gas at 100^(@)C is v. The temperature at which the r.m.s. speed will be sqrt(3)v is |
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Answer» `546^(@)C` `v_(rms)=sqrt((3RT)/(M))orv_(rms)propsqrt(T)therefore (v_(rms_(1)))/(v_(rms_(2)))=sqrt((T_(1))/(T_(2)))` Here, `v_(rms_(1))=v,v_(rms_(2))=sqrt(3)v` and `T_(1)=100^(@)C=100+273=373K` `therefore ((v)/(sqrt(3)v))^(2)=((373)/(T_(2)))or(1)/(3)=(373)/(T_(2))` `implies T_(2)=3xx373=1119K` `T_(2)=1119-273=846^(@)C`. |
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