1.

The r.m.s. velocity of molecules of a gas of density 4kg //m^(3) and pressure 1.2 xx 10^(5) N//m^(2)is

Answer»

`900ms^(-1)`
`120ms^(-1)`
`600ms^(-1)`
`300 ms^(-1)`

Solution :The r.m.s VELOCITY of a GAS `=sqrt((3P)/d)`
given `P=1.2xx10^(5)Nm^(-2)`
`d=4kgm^(-3)`
`:.v_(RMS)=sqrt((3xx1.2xx10^(5))/4)=sqrt(0.9xx10^(5))`
`=sqrt(9xx10^(4))=3XX10^(2)`
`=300ms^(-1)`


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