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The radii of curvatur of the faces of a double convex lens are 10cm and 15 cm. If focal length of the lens is 12 cm, find the refractive index of the material of the lens. |
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Answer» Solution :`(1)/( F) = ( mu -1) ((1 )/( R_(1) ) - ( 1)/( R_(2)))` `(1)/( 12) = ( mu - 1) ((1)/( 10) - ( 1)/( - 15))` `RARR mu = 1.5 ` |
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