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The radii of curvature of both the sides of a convex lens are 15 cm and if the refractive index of the material of the lens is 1.5, then focal length of lens in air is ......... cm. |
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Answer» 10 `1/f=(mu-1)(1/R_1-1/R_2)` Here,taking `R_1=15,R_2=-15,mu=1.5,` `THEREFORE 1/f=(1.5-1)((2)/(15))=(0.5xx2)/(15)` `implies f=(15xx10)/(5xx2)`=15 CM |
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