InterviewSolution
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InterviewSolution
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The radii of two planets are respectively `R_(1) and R_(2)` and their densities are respectively `rho_(1) and rho_(2)`.The ratio of the accelerations due to gravity at their surface isA. `(R_(2))/(R_(1))(rho_(1))/(rho_(2))`B. `(R_(1))/(R_(2))(rho_(2))/(rho_(1))`C. `(R_(1)rho_(1))/(R_(2)rho_(2))`D. `sqrt((R_(1)rho_(2))/(R_(2)rho_(1)))` |
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Answer» Correct Answer - C `g=(GM)/(R^(2))=G(4)/(3)(pi R^(3)rho)/(R^(2))=(4)/(3)pi GR rho` `therefore (g_(1))/(g_(2))=(R_(1)rho_(1))/(R_(2)rho_(2))` |
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