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The radioactivity of given sample of whiskey due to tritium (Half life= 12 yrs ) was found to be only 3.125% that measured in a recently purchased bottle marked " 10 years old", By how many years age the sample must have been prepared ? |
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Answer» Solution :`m/m_(0) =1/(2^n)implies (3.125)/(100) =1/(2^n)n = 5 = t/T` `t = 5T = 5XX 12 = 60` years . `:.` Total AGE of SAMPLE `= 60+10=70` years |
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