1.

The radius of ""_(29)Cu^(64) nucleus in Fermi is : ("given "R_(0)=1.2 xx 10^(-15)m)

Answer»

9.6
4.8
1.2
7.7

Solution :`R=R_(0) A^(1//3) =1.2 xx 10^(-15) xx (64)^(1//3)`
`=4.8 xx 10^(-15) m`
`=4.8" FERMI"`


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