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The radius of a charged hollow sphere is 10 cm. If V is the potential of a point away from 5 cm from the centre of sphere, then what will be potential of a point away from 15 cm from the centre of sphere ? |
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Answer» `(V)/(3)` `V_(1)= (kq)/(R) = (kq)/(10)......... (1)` For a point r (r `gt` 10 cm) from a centre of a hollow sphere, the potential `V_(2) =(kq)/(r) = (kq)/(15) .......... (2)` `:. (V_(2))/(V_(1))=(10)/(15) =(2)/(3) :. V_(2)=(2)/(3) V_(1)=(2)/(3)xxV=(2V)/(3)` |
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