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The radius of a planet is twice that of the earth but its average density is the same. If the escape speed at the planet and at the earth are `v_(p)` and `v_(e)`, respectively, then prove that `v_(p)=2v_(e)` |
Answer» `v_(e)sqrt((2GM)/R)=sqrt((2G)/Mxx4/3piR^(3)rho)=Rsqrt((8pi)/3GKrho)` `(v_(p))/(v_(e))=(R_(p))/(R_(e))=(2R_(e))/(R_(e))=2` or `v_(p)=2v_(e)` |
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