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The radius of a wheel of car is `0.4m`. The car is accelerated from rest by an angular acceleration of `1.5 rad//s^(2)` for `20 s`. How much distance will the wheel cover in this time and what will be its linear velaocity ? |
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Answer» Here, `r = 0.4m, omega_(1) = 0`, `alpha = 1.5 rad//s^(2), t = 20 s, theta = ?`, From `theta = omega_(1) + (1)/(2) alpha t^(2) = 0 + (1)/(2) xx 1.5 (20)^(2)` `= 300 rad`. Distance covered, `s = r theta = 0.4 xx 300 m` `= 120 m` Again, `omega_(2) = omega_(1) + alpha t = 0 + 1.5 xx 20` `= 30 rad//s` `upsilon = r omega_(2) = 0.4 xx 30 = 12 m//s` |
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