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The radius of an atom of an element is 55 pm. What is the edge length of the unit cell if it is body-centred cubic?(a) 144.6 pm(b) 163.4 pm(c) 127.0 pm(d) 123.5 pmThe question was posed to me in an interview for job.My enquiry is from Solid State in section Solid State of Chemistry – Class 12

Answer»

The correct OPTION is (c) 127.0 PM

The EXPLANATION is: Given,

Interionic radius (r) = 55 pm

Edge length (a) =?

For BCC, r = \(\BIG(\frac{\sqrt{3}}{4}\Big)\) x a

Or a = \(\Big(\frac{4}{\sqrt{3}}\Big)\) x r= 4 x 55/1.732 = 127 pm.



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