1.

The radius of curvature of eachface of biconcave lens, made of glass of refractive index 1.5 is 30 cm. Calculate the focal length of the lens in air.

Answer»

Solution :Here `n = 1.5 , R_(1) = - 30 CM , R_(2) = 3 cm`
Using len.s maker.s formula,
`(1)/(F) = (n-1)((1)/(R_(1))-(1)/(R_(2)))`
`=(1.5-1)[(1)/(-30)-(1)/(30)]=0.5xx((-2)/(30))`
`(1)/(f) = - (1)/(30)`
f = - 30 cm


Discussion

No Comment Found

Related InterviewSolutions