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The radius of germanium `(Ge)` nuclide is measured to be twice the radius of `._(4)^(9)Be`. The number of nucleons in `Ge` areA. 73B. 74C. 75D. 72 |
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Answer» Correct Answer - D `R=R_(0)A^(1//3)impliesA_(G_(e))=((R_(G_(E)))/R_(V_(e)))^(3)(A_(B_(e)))=(2)^(3)(9)` `8xx9=72` |
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