1.

The radius of gyration of a uniform solid sphere of radius R., about an axis passing through a point R/2 away from the centre of the sphere is:

Answer»

`sqrt((13)/(20))R`
`sqrt((23)/(40))R`
`sqrt((23)/(20))R`
`sqrt((13)/(40))R`

Solution :`I _(AB)=I_(CD) + Nd ^(2)`
`=2/5 MR ^(2) + (MR^(2))/(4)`
`= (13 MR ^(2))/(20)`
RADIUS of gyratin `= sqrt((I _(AB))/(M )) = sqrt((13 R ^(2))/(20))= sqrt((13)/(20))R`


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