InterviewSolution
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InterviewSolution
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The radius of hydrogen atom in its ground state is `5.3 xx 10^-11 m`. After collision with an electron it is found to have a radius of `21.2 xx 10^-11 m`. The principal quantum number of the final state of the atom is.A. n=4B. n=4C. n=16D. n=3 |
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Answer» Correct Answer - B ` r prop n^(2)` i.e, ` (r_(f))/( r_(i))=((n_(f))/(n_(i)))^(2)` `implies (21.2 xx 10^(-11))/(5.3xx10^(-11))=[(n)/(1)]^(2)` `implies n^(2)=4` `implies n=2 ` |
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