The radius of hydrogen atom in the ground state is `5.3 xx 10^(-11)` m. When struck by an electron, its radius is found to be `21.2 xx 10^(-11) m`. The principal quantum number of the final state will beA. 1B. 2C. 3D. 4

The radius of hydrogen atom in the ground state is `5.3 xx 10^(-11)` m

1.	The radius of hydrogen atom in the ground state is `5.3 xx 10^(-11)` m. When struck by an electron, its radius is found to be `21.2 xx 10^(-11) m`. The principal quantum number of the final state will beA. 1B. 2C. 3D. 4
Answer» Correct Answer - B `r_(n) prop n^(2)` `(n^(2)/(n^(2)) = (21.2 xx 10^(-11))/(5.3 xx 10^(-11)))` or `(n^(2)/(n^(2))) = 4` or `(n^(2)/(1^(2))) = 4` or `n = 2`

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The radius of hydrogen atom in the ground state is `5.3 xx 10^(-11)` m. When struck by an electron, its radius is found to be `21.2 xx 10^(-11) m`. The principal quantum number of the final state will beA. 1B. 2C. 3D. 4

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