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The radius of innermost electron orbit of a hydrogen atom is 5.3 xx 10^(-11) m. What is the radius of orbit in the second excited state ? |
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Answer» SOLUTION :RADIUS of innermost (n = 1) electron orbit of a hydrogen atom `r_(1)=5.3 XX 10^(-11 m` `therefore ` Radius of orbit in the second excited STATE (n = 3) will be `r= r_(1)(n)^(2)1 = 5.3 xx 10^(-11) xx (3)^(2) = 4.77 xx 10^(-10) m = 4.8 xx 10^(-10)` m |
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