1.

The radius of La^(3-) (at. No. 57) is 1.06 Å, Which one of the following given values will be closest to the radius of Lu^(3-) (at. No. 71)?

Answer»

1.60 A
1.40 A
1.06 A
0.85 A

Solution :SINCE ionic RADII of lanthanoids decrease along the SERIES then ionic radii of `Lu^(3+)(Z=71)` must be much SAMMER than that of `La^(3+)` (atomic NUMBER 57). Hence ionic radii of `Lu^(3+)` should be close to `0.85Å`.


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