1.

The radius of nucleus is R=R_(0)A^(1//3)where A is the mass number of the atom. What are the dimensions of R_(0) ?

Answer»

`[M^(0)L^(0)T^(-1)]`
`[M^(0)LT^(0)]`
`[ML^(2)T^(-2)]`
`[M^(0)L^(0)T^(0)]`

Solution :Here `R=R_(0)A^(1//3)`
`R_(0)=(R)/(A^(1//3))=(L^(1))/([M^(0)L^(0)T^(0)]^(1//3))`
`=[M^(0)L^(1)T^(0)]`
Hence CORRECT CHOICE is `(b)`.


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