The radius of the circular conducting loop shown in figure is R. Magnetic field is decreasing at a constant rate alpha. Resistance per unit length of the loop is rho. then current in wire AB is (AB is one of the diameter)

The radius of the circular conducting loop shown in figure is R. Magne

1.	The radius of the circular conducting loop shown in figure is R. Magnetic field is decreasing at a constant rate alpha. Resistance per unit length of the loop is rho. then current in wire AB is (AB is one of the diameter)
Answer» `(Ralpha)/(2RHO)` from `A` to `B` `(Ralpha)/(2rho)` from `B` to `A` `(2Ralpha)/(2rho)` from `A` to `B` zero Solution :According to Lenz's law, e.m.f. of the same MAGNITUDE in the clockwise direction are induced in the two LOOPS into which the figure is DIVIDED. So, current is induced in the clockwise direction in the outer boundary but no current in wire `Ab`.

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The radius of the circular conducting loop shown in figure is R. Magnetic field is decreasing at a constant rate alpha. Resistance per unit length of the loop is rho. then current in wire AB is (AB is one of the diameter)

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