The radius of the earth is `6400 km` and `g=10m//sec^(2)`. In order that a dody of `5 kg` weight zero at the equator, the angular speed of the earth isA. `(1)/(80)` radian/sec.B. `(1)/(800)` radian/sec.C. `(1)/(200)` radian/sec.D. `(1)/(400)` radian/sec.

The radius of the earth is `6400 km` and `g=10m//sec^(2)`. In order th

1.	The radius of the earth is `6400 km` and `g=10m//sec^(2)`. In order that a dody of `5 kg` weight zero at the equator, the angular speed of the earth isA. `(1)/(80)` radian/sec.B. `(1)/(800)` radian/sec.C. `(1)/(200)` radian/sec.D. `(1)/(400)` radian/sec.
Answer» Correct Answer - B `mR omega^(2)=mg` `therefore omega = sqrt((g)/(R ))=sqrt((10)/(6400xx10^(3)))=(1)/(800)` rad/s

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The radius of the earth is `6400 km` and `g=10m//sec^(2)`. In order that a dody of `5 kg` weight zero at the equator, the angular speed of the earth isA. `(1)/(80)` radian/sec.B. `(1)/(800)` radian/sec.C. `(1)/(200)` radian/sec.D. `(1)/(400)` radian/sec.

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