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The radius of the first orbit of hydrogen atom is 0.5 Å. The electron moves is an orbit with a uniform speed of 2.2xx10^(6) ms^(-1). What is the magnetic field produced at the centre of the uncleus due to the mation of this electron ? Use mu_(0)= 4pi xx 10^(-7) Hm^(-1) and electric charge=1.6 xx 10^(-19) C |
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Answer» Solution :Here, `"" r = 0.5 Å xx 10^(-10) `m V = 2.2 `xx 10^(6) ms^(-1)` period of revolution of electron T = `(2pi r)/(v) = (2 xx 22 xx 0.5 xx 10^(-10))/(7 xx 2.2 xx 10^(6)) = (1)/(7) xx 10^(-15)`S Equivalent CURRENT, I = `("charge")/("time") = (E)/(T) = (1.6xx 10^(-19) xx 7)/(10^(-15)) ` Magnetic FIELD produced at the centre of the nucleus, `B = (mu_(0)I)/(2r) = (4pi xx 10^(-7) xx 1.12 xx 10^(-3))/(2 xx 0.5xx 10^(-10))` B = 14.07 T |
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