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The radius of the innermost electron orbit of a hydrogen atom is 5.3 xx 10^(–11) m. What are the radii of the n = 2 and n =3 orbits? |
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Answer» SOLUTION :`r_(0)=a_(0)=5.3xx10^(-11)m` `:. In n=2,r ^(2)=?` In `n=3, r^(3)=?` `rArr` Radius of electron in `n^(TH)` orbit in HYDROGEN atom `r_(n)=n^(2)r_(0)` Radius in n=2 orbit, `r_(2)=(2)^(2)xx5.3xx10^(-11)` `=4xx5.3xx10^(-11)` `:.r_(@) =2.12xx10^(-10)m` Radiusin n=3 orbit, `r_(3)=(3)^(2)xx5.3xx10^(-11)` `=9xx5.3xx10^(-11)` `:.r_(3)=4.77xx10^(-10)m` |
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