Saved Bookmarks
| 1. |
The radius of the innermost electron orbit of a hydrogen atom is 5.3 xx 10^(-11) m. What are the radii of the n = 2 and n = 3 orbits ? |
|
Answer» SOLUTION :As `r_(n)=n^(2)R` `therefore r_(2)=4r_(1)=4xx5.3xx10^(-11)m=2.12 xx10^(-10)m` and `r_(3)=9r_(1)=9xx5.3xx10^(-11)m=4.77xx10^(-10)m` |
|