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The radius of theinnermostelectron orbit of a hydrogenatomis 5.3 xx 10^(-11)m . Whatare theradii of the n = 2 and n = 3 orbits? |
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Answer» SOLUTION :It is given that RADIUS of the innermost (n = 1) electron orbit of HYDROGEN ATOM `r_(1) =5.3 xx 10^(-11) m` and `therefore`Radii of the orbit corresponding to `n=2, r_(2)= (2)^(2) xx r_(1) = 4 xx 5.3 xx 10^(-11) m = 2.12 xx 10^(-10) m` and radii of the orbit corresponding to `n=3, r_(3) = (3)^(2) xx r_(1) - 9 xx 5.3 xx 10^(-11) m = 4.77 xx 10^(-11) m` |
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