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The range of the function f(x) = \(\frac{x+2}{|x+2|}\),x ≠ -2 isA. {-1, 1} B. {-1, 0, 1} C. {1} D. (0, ∞) |
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Answer» Option : (A) f(x) = (x+2)/|x+2| When x>-2, We have, f(x) = \(\frac{x+2}{x+2}\) = 1 When x<-2, We have, f(x) = \(\frac{x+2}{-(x+2)}\) = -1 R(f) = {-1, 1} |
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