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The range of the function f(x) = \(\frac{x^2-x}{x^2+2x}\) isA. R B. R –{1} C. R – {-1/2, 1} D. None of these |
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Answer» Option : (C) Let y = (x2-x)/(x2+2x) y(x2+2x) = x2-x yx(x+2) = x(x-1) y(x+2) = x-1 x(y-1) = -(1+2y) x = \(-\frac{(1+2y)}{y-1}\) Value of x can’t be zero or it cannot be not defined.. y≠1, -1/2 So, Range = R-{-1/2, 1} |
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