1.

The range of the function f(x) = \(\frac{x^2-x}{x^2+2x}\) isA. R B. R –{1} C. R – {-1/2, 1} D. None of these

Answer»

Option : (C)

Let y = (x2-x)/(x2+2x)

y(x2+2x) = x2-x 

yx(x+2) = x(x-1) 

y(x+2) = x-1

x(y-1) = -(1+2y)

x = \(-\frac{(1+2y)}{y-1}\) 

Value of x can’t be zero or it cannot be not defined.. 

y≠1, -1/2 

So, 

Range = R-{-1/2, 1}



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